-2x^2-36x-18=0

Solution for -2x^2-36x-18=0 equation:

-2x^2-36x-18=0

a = -2; b = -36; c = -18;
Δ = b2-4ac
Δ = -362-4·(-2)·(-18)
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-24\sqrt{2}}{2*-2}=\frac{36-24\sqrt{2}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+24\sqrt{2}}{2*-2}=\frac{36+24\sqrt{2}}{-4}
$